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Μάθημα: AP®︎ Λογισμός BC > Ενότητα 6
Μάθημα 10: Finding antiderivatives and indefinite integrals: basic rules and notation: definite integrals- Ορισμένα ολοκληρώματα: κανόνας αντίστροφης δύναμης
- Ορισμένα ολοκληρώματα: κανόνας αντίστροφης δύναμης
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- Ορισμένα ολοκληρώματα συναρτήσεων σε κλάδους
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Ορισμένα ολοκληρώματα: κανόνας αντίστροφης δύναμης
Examples of calculating definite integrals of polynomials using the fundamental theorem of calculus and the reverse power rule.
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- [Instructor] Let's evaluate
the definite integral from negative three to five of four DX. What is this going to be equal to? I encourage you to pause the video and try to figure it out on your own. Alright, so in order to evaluate this we need to remember the
fundamental theorem of calculus which connects the notion
of a definite integral and an anti-derivative. So, the fundamental theorem
of calculus tells us that our definite integral from A to B of F of X, DX is going to be equal
to the anti-derivative of our function F which we
denote with a capital F, evaluated at the upper bound minus our anti-derivative
evaluated at the lower bound. So, we just have to do
that right over here. So, this is going to be equal to? Well, what is the anti-derivative of four? Well, you might immediately say well, that's just going to be four X. You can even think of it in
terms of reverse power rule. Four is the same thing
as four X to the zero so you increase zero by one, so it's going to be four X to the first and then you divide by that new exponent. So, four X to the first divided by four, well, that's just gonna be four X. So, the anti-derivative is four X. This is you could say our capital F of X. And we're going to evaluate that at five and at negative three and we're going to find the difference between these two. So, what we have right over here evaluating the anti-derivative
at our upper bound that is going to be four times five and then from that we're going to subtract evaluating our anti-derivative
at the lower bound, so that's four times negative three, four times negative three and what is that going to be equal to? So, this is 20 and then minus negative 12, so this is going to be plus 12 which is going to be equal to 32. Let's do another example where we're going to do
the reverse power rule. So, let's say that we want
to find the indefinite or we want to find the definite integral going from negative one to three of seven X squared DX. What is this going to be equal to? Well, what we want to do is evaluate what is the anti-derivative of this or you could say if this
is lowercase F of X, what is capital F of X? Well, the reverse power rule we increase this exponent by one, so we're going to have
seven times X to the third and then we divide by
that increased exponent, so seven X to the third divided by three and we want to evaluate
that at our upper bound and then subtract from that and evaluate it at our lower bound. So, this is going to be equal to? So, evaluating it at our upper bound it's going to be seven
times three to the third, I'll just write that three to the third over three and then from that we are going to subtract
this capital F of X, the anti-derivative
evaluated the lower round. So, that is going to be seven times negative one to the third, all of that over three. And so, this first expression, let's see, this is going to be seven times three to the third over three, this is 27 over three, this is going to be the same
thing as seven times nine. So, this is gonna be 63 and this over here, negative one to the third
power is negative one but then we were subtracting a negative, so this is just gonna be adding and so, this is just gonna
be plus seven over three, plus seven over three. If we wanted to express
this as a mixed number, seven over three is the same thing as two and one third, so when we add everything together we are going to get 65 and one third. And we are done.