If you're seeing this message, it means we're having trouble loading external resources on our website.

Εάν είστε πίσω από ένα web φίλτρο, παρακαλούμε να βεβαιωθείτε ότι οι τομείς *. kastatic.org και *. kasandbox.org δεν είναι αποκλεισμένοι.

Κύριο περιεχόμενο

Factoring polynomials: common binomial factor

Sal factors n(n-1)+3(n-1) as (n+3)(n-1) by noticing that (n-1) is a common factor.

Θέλετε να συμμετάσχετε σε μια συζήτηση;

Δεν υπάρχουν αναρτήσεις ακόμα.
Μπορείς να διαβάσεις στα Αγγλικά; Κάνε κλικ εδώ για να δείτε περισσότερες συζητήσεις που συμβαίνουν στην αγγλική ιστοσελίδα της Khan Academy.

Απομαγνητοφώνηση βίντεο

- Whereas to factor the polynomial below as the product of two binomials and we have n times n minus one plus 3 times n minus one. So I encourage you to pause this video and see if you can figure this out. Well, the key is to realizing that both of these terms have n minus one as a factor. Let me just rewrite the whole thing so we can work on it down here. So this is n times n minus one plus 3 times n minus one. And notice both of them have an n minus one, have an n minus one as a factor. So what we can do is factor out the n minus one or you can view it as undistributing the n minus one and if we do that, we're gonna factor out the n minus one and what are we going to have left over? Well if you take out the n minus one here if you undistribute it out, you're just going to be left with that n. So you're going to have an n there and then for this second term, you factor this n minus one out. You're just going to be left with this positive three plus three. And just like that we are done. We have factored the polynomial below as a product of two binomials. So this is the same thing as n minus one times n plus three. And once again you can check this. You can take this n minus one and distribute it. n minus one times n is this term right over here n times n minus one and then n minus one times three is this term right over here. n minus one times three or three times n minus one.